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PROOF 95

Prove.

√a is fixed as the nonnegative one

On the real numbers ℝ.

A way to read this proof

First separate what is assumed from what is to be proved. At each step, ask which definition or earlier result permits the move. If it is unclear, return to that premise rather than skipping to the conclusion.

Definition D1

For a > 0, √a denotes an x satisfying x² = a.

Proof.

(1)A square root asks squaring in reverse: what number, squared, gives a?convention
(2)If several such x exist, this definition does not say which one √a refers to.convention

∎

Definition D2

When x² = a has several solutions, √a denotes the nonnegative one among them.

Proof.

(1)For the symbol √a to refer to a single value, each input a must have a single output.F
(2)Therefore, when there are several solutions, a convention must choose one of them.(1), D1
(3)The nonnegative one is chosen.convention

∎

Lemma L1

If a > 0, the only reals satisfying x² = a are x and −x, one positive and the other negative.

Proof.

(1)There exists x > 0 with x² = a.A1
(2)(−x)² = x² = a, so −x is also a solution.(1), A2, E
(3)x > 0, so −x < 0.(1), A5
(4)x and −x are two distinct solutions.(1), (2), (3), A4
(5)Take y with y² = a and y ≥ 0.assumption
(6)If x ≠ y, then x < y or y < x.A4
(7)Either way, x² ≠ y².(6), A3, A4
(8)x² = y² = a, so this is a contradiction, and therefore x = y.(1), (5), (7), E
(9)If z < 0 and z² = a, then −z > 0 and (−z)² = a.A2, A5, E
(10)By (8), −z = x, so z = −x.(8), (9)
(11)Therefore the only solutions are x and −x.(4), (8), (10)

∎

Theorem T

If a > 0, then √a is uniquely determined, √a ≥ 0 and (√a)² = a.

Proof.

(1)The only solutions of x² = a are x and −x.L1
(2)x > 0 and −x < 0, so there is exactly one nonnegative solution.(1), A5, A4
(3)D2 fixes that one as √a.(2), D2
(4)Therefore √a ≥ 0 and (√a)² = a.(3), D1, D2

∎

Corollary C

The solutions of x² = 4 are x = 2 and x = −2, but √4 = 2.

Proof.

(1)2 × 2 = 4, so 2 is a solution of x² = 4.A6, D1
(2)The only solutions are 2 and −2.(1), L1
(3)The nonnegative one of the two is 2.(2), A5
(4)Therefore √4 = 2.(3), D2
(5)The equation's solutions are x = ±2, and the symbol √4 refers to only one of them. The two sentences are different.(2), (4)

∎

Remark

Can F be removed from this proof?

That there are two solutions and that the symbol √ refers to one value are different sentences.