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PROOF 171

Prove.

The standard deviation returns to the original unit

On finite data.

A way to read this proof

First separate what is assumed from what is to be proved. At each step, ask which definition or earlier result permits the move. If it is unclear, return to that premise rather than skipping to the conclusion.

Definition D1

Let dᵢ = xᵢ − x̄. Then σ² = (Σdᵢ²)n⁻¹ is called the variance and σ = √(σ²) the standard deviation.

Proof.

(1)Σaᵢ denotes a₁ + ⋯ + aₙ, u − v denotes u + (−v), and t² denotes t·t. By associativity and commutativity of addition, this sum is uniquely determined regardless of the order and grouping of terms.convention, A1, A2
(2)Since n ≥ 1, we have n ≠ 0 and n⁻¹ exists.A10, A6
(3)The square root is taken as the non-negative root, so σ is uniquely determined and 0 ≤ σ.A11

∎

Definition D2

For a constant c, the data obtained by yᵢ = c xᵢ are called the data x scaled by c.

Proof.

Just as lengths are rewritten from m to cm, changing units is precisely scaling the data by a constant.convention

∎

Lemma L1

If yᵢ = c xᵢ, then ȳ = c x̄.

Proof.

(1)n ȳ = Σyᵢ = Σ(c xᵢ)A9, D2
(2)Σ(c xᵢ) = c Σxᵢ(1), A8
(3)Since Σxᵢ = n x̄, n ȳ = c(n x̄)(2), A9, E
(4)c(n x̄) = n(c x̄)A4, A5
(5)Since n ≠ 0, cancelling n gives ȳ = c x̄(3), (4), A10, A7

∎

Theorem T1

If yᵢ = c xᵢ, then σ_y² = c² σ_x².

Proof.

(1)yᵢ − ȳ = c xᵢ + (−(c x̄)) = c xᵢ + c(−x̄) = c(xᵢ − x̄)D2, L1, A15, A3
(2)(yᵢ − ȳ)² = (c dᵢ)² = c² dᵢ²(1), D1, A4, A5
(3)Σ(yᵢ − ȳ)² = Σ(c² dᵢ²) = c² Σdᵢ²(2), A8
(4)σ_y² = (c² Σdᵢ²)n⁻¹ = c²((Σdᵢ²)n⁻¹) = c² σ_x²(3), D1, A4, A5
(5)The data 1, 1, 3, 3 have x̄ = 2, dᵢ = −1, −1, 1, 1, Σdᵢ² = 4, so σ_x² = 1.A9, D1, N
(6)If c = 100, the data are 100, 100, 300, 300 with ȳ = 200, Σ(yᵢ − ȳ)² = 40000, σ_y² = 10000.(5), D2, L1, D1, N
(7)100² × 1 = 10000, consistent with (4).(4), (5), (6), N

∎

Theorem T2

If yᵢ = c xᵢ, then σ_y = |c| σ_x.

Proof.

(1)σ_y = √(σ_y²) = √(c² σ_x²)D1, T1
(2)c² σ_x² = (c σ_x)²A4, A5
(3)√((c σ_x)²) = |c σ_x|(2), A12
(4)|c σ_x| = |c| |σ_x|(3), A13
(5)Since 0 ≤ σ_x, |σ_x| = σ_xD1, A11, A14
(6)Therefore σ_y = |c| σ_x(1), (3), (4), (5)
(7)For the data 1, 1, 3, 3, σ_x = √1 = 1, and if c = 100 then σ_y = √10000 = 100 = |100| × 1.T1, D1, A11, N
(8)If c = −1, the data are −1, −1, −3, −3 with σ_y² = 1, σ_y = 1. Since c σ_x = −1, the factor is |c|, not c.T1, D1, A11, N

∎

Corollary C

The only quantity that scales by the same factor as the data is the standard deviation.

Proof.

(1)Scaling the data by c scales the mean by c and the variance by c².L1, T1
(2)The standard deviation scales by |c|, the same factor as the data.T2
(3)Rewriting lengths from m to cm means c = 100. Then the variance grows by a factor of 10000 and the standard deviation by a factor of 100.D2, T1, T2, N
(4)Therefore the variance moves by a different factor than the data, and cannot be read side by side with them.(1), (3)
(5)Squaring changes the factor from c to c², and the square root returns c² to |c|. The place it returns to is the place of the data.(1), (2), D1
(6)That the returned factor is |c| rather than c also has meaning: flipping the sign of all the data leaves the spread unchanged.T2, N

∎

Remark

Can A11 be removed from this proof?

Separate the lines where a square root appears from those where it does not. Check which layer rests on the convention.